Pomoc oko dodavanja slika!

Član
Učlanjen(a)
19.06.2013
Poruka
61
Moze li neko da mi objasni kako da napravimformu u kojoj cu slelektovati desetak slika iz svog racunara i klikom najednodugme ih uploudovati? Evo mog koda:


index.php

<form action="upload_file.php" method="post"
enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" value="Dodaj slike" id="file"><br>
<input type="submit" name="submit" value="Dodaj slike">
</form>



upload_file.php
<?php
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
}


$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/jpg")
|| ($_FILES["file"]["type"] == "image/pjpeg")
|| ($_FILES["file"]["type"] == "image/x-png")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 20000)
&& in_array($extension, $allowedExts))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
}
}
else
{
echo "Invalid file";
}
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/jpg")
|| ($_FILES["file"]["type"] == "image/pjpeg")
|| ($_FILES["file"]["type"] == "image/x-png")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 20000)
&& in_array($extension, $allowedExts))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";


if (file_exists("upload/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}
?>

Ovako mogu dodati jednu po jednu sliku i to funkcionise bas kako meni treba,samo sto bih ja da selektujem jedno desetak slika pa da se mogu dodati sveodjednom a ne jednu po jednu.Jel meze neko da pomogne?
 
Član
Učlanjen(a)
19.06.2013
Poruka
61
Ako je neko imao isti problem kao i ja evo resenja!

index.php

<form action="upload_file.php" method="post" enctype="multipart/form-data">
<input type="file" name="file[]" id="file1"><br>
<input type="file" name="file[]" id="file2"><br>
<input type="file" name="file[]" id="file3"><br>
<input type="file" name="file[]" id="file4"><br>
<input type="file" name="file[]" id="file5"><br>
<input type="file" name="file[]" id="file6"><br>
<input type="file" name="file[]" id="file7"><br>
<input type="file" name="file[]" id="file8"><br>
<input type="file" name="file[]" id="file9"><br>
<input type="file" name="file[]" id="file10"><br>
<input type="submit" name="submit" value="Dodaj slike">
</form>



upload_file.php

<?php

for ($i=0;$i<count($_FILES['file']['name']);$i++){
$ran_num = mt_rand().mt_rand().mt_rand().mt_rand().mt_rand();
echo "<br>";
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"][$i]);
$extension = end($temp);
if ((($_FILES["file"]["type"][$i] == "image/gif")
|| ($_FILES["file"]["type"][$i] == "image/jpeg")
|| ($_FILES["file"]["type"][$i] == "image/jpg")
|| ($_FILES["file"]["type"][$i] == "image/pjpeg")
|| ($_FILES["file"]["type"][$i] == "image/x-png")
|| ($_FILES["file"]["type"][$i] == "image/png"))
&& ($_FILES["file"]["size"][$i] < 1000000) && ($_FILES["file"]["error"][$i]==0)
&& in_array($extension, $allowedExts)){
echo "Upload: " .$ran_num. $_FILES["file"]["name"][$i] . "<br>";
echo "Type: " . $_FILES["file"]["type"][$i] . "<br>";
echo "Size: " . ($_FILES["file"]["size"][$i] / 1024) . " kB<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"][$i]."<br>";
if (file_exists("upload/".$ran_num . $_FILES["file"]["name"][$i])){
echo "<b>".$_FILES["file"]["name"][$i] . " already exists.</b><br> ";
} else {
move_uploaded_file($_FILES["file"]["tmp_name"][$i],
"upload/" .$ran_num. $_FILES["file"]["name"][$i]);
echo "<b>Uploaded to</b>: " . "upload/" .$ran_num. $_FILES["file"]["name"][$i]."<br>";
}
}
}
?>
i naravno treba vam prazan folder nazvan "upload".
Ovim kodom mogu dodati 10 slika od jednom,i ispred imena dodati random number od jedno 40-tak karaktera.Mislim daje veoma mala verovatnoca da dve slike imaju isto ime.
E sad ako moze mala pomoc!
Kako putanju te slike da smestim u bazu?
Na primer ako je Pera Peric dodao te slike da posle iz baze mogu da pozovem Perine slike i da mi izbaci te slike koje je on dodao?
Hvala svima i pozz!!
 
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